Force and Laws of Motion

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CLASS IX Science ~8 marks/year Ch 9 of 15
Force and Laws of Motion

Class 9 · Science · NCERT chapter notes · Akanksha Classes

Snapshot
  • Force is a push or pull that can change the state of motion of an object. Forces can be balanced (no net effect on motion) or unbalanced (cause acceleration).
  • Newton's First Law (Law of Inertia): Every object stays at rest or in uniform straight-line motion unless acted upon by an unbalanced external force.
  • Inertia is the natural tendency of an object to resist change in its state of motion. It is measured by mass — greater mass means greater inertia.
  • Newton's Second Law: Force equals the rate of change of momentum. Written as F = ma. The SI unit of force is the Newton (N) where 1 N = 1 kg m/s^2.
  • Momentum p = mv is a vector quantity (SI unit: kg m/s). It is the "quantity of motion" an object carries.
  • Impulse = F x t = change in momentum = mv minus mu. Impulse explains why catching a ball with drawn-back hands hurts less.
  • Newton's Third Law: Every action has an equal and opposite reaction acting on a DIFFERENT object. They never cancel.
  • Conservation of Linear Momentum: Total momentum of an isolated system is constant. Derived from Newton's Third Law. Explains gun recoil, rocket propulsion, and collision problems.
  • Board weightage: About 8 marks per year. Expect one law-statement question (3 marks), one derivation of conservation of momentum (5 marks), and numericals on F = ma and momentum conservation (2 to 3 marks each).
Detailed Notes

1. Force — Balanced and Unbalanced Forces

A force is a push or a pull. It is a vector quantity — it has both magnitude and direction. Forces can change the speed, direction, or shape of an object. The SI unit of force is the Newton (N).

What can a force do?

  • Move a stationary object (push a box on the floor).
  • Stop a moving object (braking a car).
  • Speed up a moving object (engine force on a car).
  • Slow down a moving object (friction on a rolling ball).
  • Change the direction of motion (a cricket bat deflects a ball).
  • Change the shape of an object (pressing dough, compressing a spring).

Balanced forces: When two or more forces acting on an object have a net (resultant) force of zero, the forces are called balanced. Balanced forces do NOT change the state of motion of the object. The object either stays at rest or continues moving at the same speed in the same direction.

  • Example 1: A book on a table. Gravity pulls it down; the normal reaction of the table pushes it up. Net force = 0, the book does not move.
  • Example 2: A tug-of-war where both teams pull equally. The rope does not move.
  • Example 3: A car moving at constant speed on a level road — engine force equals friction force, net force = 0.

Unbalanced forces: When the net force on an object is not zero, the forces are called unbalanced. An unbalanced force ALWAYS produces a change in speed or direction — that is, acceleration.

  • Example 1: Kicking a football — the kick force is not balanced, so the ball accelerates from rest.
  • Example 2: A car accelerating — the engine provides a force greater than friction, so there is a net forward force.
  • Example 3: A stone falling freely — gravity acts downward and is not balanced (air resistance is usually neglected), so the stone accelerates downward.

Key rule: No unbalanced force means no change in motion. This is the fundamental idea behind Newton's First Law.

2. Newton's First Law of Motion

Statement (NCERT exact): "An object remains in a state of rest or of uniform motion in a straight line unless compelled to change that state by an applied unbalanced force."

This law is also called the Law of Inertia. Galileo first showed through inclined-plane experiments that moving objects do not need a continuous force to keep moving — they naturally tend to maintain their state. Newton formalised this observation into his first law.

What the law tells us:

  1. A body at rest will remain at rest unless acted on by an unbalanced external force.
  2. A body moving at constant speed in a straight line will continue doing so unless acted on by an unbalanced external force.
  3. Any change in speed OR direction requires an unbalanced force.

Types of Inertia — Three Kinds:

1. Inertia of Rest: The tendency of a body to remain at rest when it is at rest.

  • When a bus starts suddenly, passengers lurch backward — their bodies tend to remain at rest while the bus moves forward.
  • Dust particles fly off when a carpet is beaten — the carpet moves suddenly but the dust particles tend to stay where they are.
  • A coin placed on a card resting on a glass falls straight into the glass when the card is flicked away quickly — the coin stays in place due to inertia of rest while the card moves.
  • Seeds fall straight down from a shaken tree — the branch is shaken but the seeds tend to remain at rest.

2. Inertia of Motion: The tendency of a body to remain in motion when it is already moving.

  • When a bus brakes suddenly, passengers jerk forward — their bodies tend to keep moving while the bus slows down.
  • An athlete runs a few steps beyond the finish line even after stopping effort — the body tends to continue moving.
  • A ball rolling on a frictionless surface would roll forever — no force is needed to maintain motion.

3. Inertia of Direction: The tendency of a body to maintain its direction of motion.

  • Water flies off tangentially from a spinning wet grindstone when it stops suddenly.
  • A stone tied to a string and whirled in a circle flies off in a straight line tangent to the circle if the string breaks — it tends to keep moving in the direction it was travelling at that instant.
  • When a car turns a corner, passengers feel pushed to the outside — their bodies tend to maintain the original direction of motion.

3. Inertia and Mass

Inertia is the natural resistance of an object to any change in its state of rest or of uniform motion. It is NOT a force — it is an inherent property of matter.

Different objects have different amounts of inertia. The physical quantity that measures inertia is mass. This is one of the most important statements in NCERT:

Mass of an object is a measure of its inertia.

The more mass an object has, the more inertia it has, and the harder it is to change its state of motion.

Comparing inertia:

  • A cricket ball has more inertia than a table-tennis ball — it is harder to set in motion and harder to stop with the same force.
  • A loaded truck has far more inertia than an empty one — much larger force (braking force, engine force) is needed to change its state of motion.
  • A heavy stone cannot be kicked as easily as a light pebble — greater mass, greater inertia.
  • It is easier to push an empty shopping trolley than a full one — the full one has greater mass and thus greater inertia.

Mass vs Weight: Mass (measured in kg) is a measure of the amount of matter and is the measure of inertia. Weight (measured in N) is the gravitational force on the object. Inertia depends on mass, not on weight. An astronaut in space (weightless) still has mass and still has inertia — a floating wrench is still hard to set spinning quickly.

4. Newton's Second Law of Motion

Before stating the second law, we define momentum:

Momentum (p): The momentum of an object is defined as the product of its mass (m) and its velocity (v).

p = mv

Momentum is a vector quantity in the direction of velocity. SI unit of momentum is kg m/s, which is the same as N s.

Momentum captures "quantity of motion". A heavy truck moving slowly can have the same momentum as a light car moving fast. Momentum tells us how hard it is to bring the object to rest.

Statement of Newton's Second Law (NCERT): "The rate of change of momentum of an object is directly proportional to the applied unbalanced force in the direction of force."

Mathematical derivation (NCERT method):

Let an object of mass m have initial velocity u and final velocity v after time t under the action of constant net force F.

  • Initial momentum: p_i = mu
  • Final momentum: p_f = mv
  • Change in momentum: Delta p = mv minus mu = m(v minus u)
  • Rate of change of momentum = Delta p / t = m(v minus u) / t
  • Acceleration a = (v minus u) / t
  • So rate of change of momentum = m x a

By Newton's Second Law, F is proportional to rate of change of momentum:

F = ma

More generally, when mass can also change:

F = dp/dt

Definition of 1 Newton (N): One Newton is that force which produces an acceleration of 1 m/s^2 in a body of mass 1 kg. So 1 N = 1 kg x 1 m/s^2 = 1 kg m/s^2.

Key points about F = ma:

  • F here is the net unbalanced force on the object.
  • The direction of a is the same as the direction of F.
  • If F = 0, then a = 0 — this reproduces Newton's First Law, so the First Law is a special case of the Second Law.
  • For a given force, larger mass gives smaller acceleration (harder to accelerate heavy things).
  • For a given mass, larger force gives larger acceleration.
  • F = ma is valid for constant mass; otherwise use F = dp/dt.

5. Impulse

Sometimes a large force acts for a very short time — such as a bat hitting a ball, a hammer driving a nail, or two cars colliding. In such cases, we define Impulse:

Impulse J = F x t = Delta p = mv minus mu

Impulse is the product of force and time. It equals the change in momentum. SI unit: N s (same as kg m/s).

Impulse is useful because:

  • When force is not constant during a collision, we can still compute the change in momentum = average force x time.
  • The change in momentum (impulse) is fixed by the initial and final speeds — only the force and time can vary: large force for short time, OR small force for long time.

Everyday applications of Impulse:

  • Catching a cricket ball: A fielder draws his hands back while catching. The ball's momentum must become zero (fixed change). By increasing time of contact, the force on hands decreases. This is why the catch hurts less.
  • Car crumple zones and air bags: In a collision, the car must stop (change in momentum is fixed). Crumple zones and air bags increase the time of deceleration, so the force on passengers is much smaller, reducing injury.
  • High-jump landing on foam: The foam increases contact time, reducing the impact force on the athlete's body.
  • Karate chop: The expert strikes with a very short contact time. This means even a moderate impulse (change in momentum) produces a very large peak force — enough to break bricks.
  • Jumping into a haystack vs a hard floor: The haystack gives during impact, increasing the time for momentum to reduce to zero, so the force is much smaller and injury is avoided.

6. Newton's Third Law of Motion

Statement (NCERT exact): "To every action, there is an equal and opposite reaction and they act on two different objects."

Four key ideas packed in this law:

  1. Forces always occur in pairs. You cannot have a lone force; every force has a reaction.
  2. Action and reaction are equal in magnitude.
  3. Action and reaction are opposite in direction.
  4. Action and reaction act on two different objects — NEVER on the same object. This is why they do NOT cancel each other.

Examples from daily life:

  • Walking: You push the ground backward with your foot (action). The ground pushes you forward (reaction). This forward reaction force propels you.
  • Swimming: A swimmer pushes water backward with hands and feet (action). Water pushes the swimmer forward (reaction).
  • Rowing a boat: The oar pushes water backward (action). Water pushes the oar — and thus the boat — forward (reaction).
  • Rocket propulsion: The rocket engine burns fuel and pushes hot exhaust gases backward at very high speed (action). The gases push the rocket forward (reaction). Crucially, this works in outer space where there is no air to "push against" — the rocket only needs to push its own exhaust gases.
  • Gun recoil: When a gun is fired, it exerts a force on the bullet, sending it forward (action). The bullet exerts an equal and opposite force on the gun, causing the gun to recoil backward (reaction). Because the gun has much greater mass than the bullet, its recoil velocity is much smaller.
  • Jumping off a boat: You push the boat backward (action). The boat pushes you forward (reaction). Since the boat has less friction with water, it slides backward as you jump forward.
  • Inflated balloon released: Air rushes out of the balloon backward (action). The balloon moves forward (reaction). This is the same principle as rocket propulsion.

Common misconception — action and reaction DO NOT cancel: They are equal and opposite, but they act on two different bodies. The ground's push on you (forward) and your push on the ground (backward) do not cancel because they act on different objects. If they acted on the same object they would cancel, but they do not.

7. Conservation of Linear Momentum

Statement: "The total momentum of an isolated system of objects remains constant (is conserved) provided no external unbalanced force acts on the system."

Complete NCERT derivation from Newton's Third Law:

Consider two objects A (mass m_A, initial velocity u_A) and B (mass m_B, initial velocity u_B) that interact (collide) for a time interval t. Let their velocities after the collision be v_A and v_B.

During the collision:

  • Force exerted by A on B = F_AB (action)
  • Force exerted by B on A = F_BA (reaction)
  • By Newton's Third Law: F_AB = minus F_BA

By Newton's Second Law applied to A and B separately (same time t for both):

  • F_BA = m_A(v_A minus u_A) / t
  • F_AB = m_B(v_B minus u_B) / t

Since F_AB = minus F_BA:

m_B(v_B minus u_B) / t = minus m_A(v_A minus u_A) / t

Multiplying both sides by t and rearranging:

m_A u_A + m_B u_B = m_A v_A + m_B v_B

Total momentum before collision = Total momentum after collision. This is the Law of Conservation of Linear Momentum.

Condition for validity: No external unbalanced force must act on the system. For example, in a gun-bullet system just at the instant of firing, gravity and the floor's normal force cancel (balanced external forces), so total momentum is conserved. Before firing, both gun and bullet are at rest, so total momentum = 0. After firing:

m_bullet x v_bullet + M_gun x V_gun = 0

This means: m_bullet x v_bullet = minus M_gun x V_gun. The bullet goes forward, the gun recoils backward with equal and opposite momentum.

Applications of Conservation of Momentum:

  • Gun recoil velocity calculation
  • Rocket and jet propulsion
  • Two objects colliding and sticking together (perfectly inelastic collision)
  • Two objects bouncing off each other (elastic collision)
  • An exploding bomb — fragments fly off so that total momentum remains zero (if bomb was at rest)

8. Key Formulae Card

p = mv    (momentum; vector; kg m/s)
F = ma = m(v minus u)/t = dp/dt    (Newton's 2nd Law; N)
Impulse J = F x t = mv minus mu = Delta p    (N s)
m_A u_A + m_B u_B = m_A v_A + m_B v_B    (Conservation of Momentum)
1 N = 1 kg m/s^2    (definition of newton)

Important relationships:

  • Inertia is measured by mass — not by weight, not by velocity.
  • Momentum has both magnitude and direction.
  • Impulse = change in momentum — useful when force x time product is given or asked.
  • Newton's First Law is a special case of the Second Law (when F = 0, a = 0).
  • Conservation of Momentum is derived from Newton's Third Law.
  • In an isolated system, if one object gains momentum, another loses the same amount in the opposite direction.

9. NCERT Worked Examples

NCERT Example 9.1 — Force on two different masses

Question: A force of 5 N gives a mass m_1 an acceleration of 10 m/s^2, and a mass m_2 an acceleration of 20 m/s^2. What acceleration would the same force give if both masses are tied together?

Solution:

From F = ma: m_1 = F/a_1 = 5/10 = 0.5 kg

m_2 = F/a_2 = 5/20 = 0.25 kg

Combined mass = m_1 + m_2 = 0.5 + 0.25 = 0.75 kg

New acceleration a = F / (m_1 + m_2) = 5 / 0.75 = 6.67 m/s^2

Answer: 6.67 m/s^2

NCERT Example 9.2 — Calculating recoil velocity of a gun

Question: A bullet of mass 20 g is horizontally fired with a velocity of 150 m/s from a pistol of mass 2 kg. What is the recoil velocity of the pistol?

Solution:

m_bullet = 20 g = 0.020 kg, v_bullet = +150 m/s (forward)

M_gun = 2 kg, V_gun = ? (backward)

Before firing: both at rest, total momentum = 0

By conservation of momentum: m_bullet x v_bullet + M_gun x V_gun = 0

(0.020)(150) + (2)(V) = 0

3 + 2V = 0

V = -1.5 m/s

Answer: The pistol recoils at 1.5 m/s in the direction opposite to the bullet.

NCERT Example 9.3 — Collision: object sticking together

Question: An object of mass 1 kg travelling in a straight line at 10 m/s collides with and sticks to a stationary wooden block of mass 5 kg. Find the velocity of the combined object after the collision.

Solution:

m_1 = 1 kg, u_1 = 10 m/s; m_2 = 5 kg, u_2 = 0

After collision (they stick): combined mass = 1 + 5 = 6 kg, velocity = v

By conservation of momentum:

m_1 u_1 + m_2 u_2 = (m_1 + m_2) v

(1)(10) + (5)(0) = (6)(v)

10 = 6v

v = 10/6 = 1.67 m/s

Answer: The combined object moves at 1.67 m/s in the original direction of the 1 kg object.

NCERT Example — Force to produce a given acceleration

Question: What is the force required to produce an acceleration of 4 m/s^2 in a body of mass 8 kg?

Solution:

F = ma = 8 x 4 = 32 N

Answer: 32 N

NCERT Example — Braking force on a car

Question: A car of mass 1500 kg is moving at 60 km/h. On applying brakes, the car stops in 5 seconds. Calculate the braking force.

Solution:

m = 1500 kg

u = 60 km/h = 60 x (1000/3600) = 50/3 m/s = 16.67 m/s

v = 0, t = 5 s

a = (v - u)/t = (0 - 16.67)/5 = -3.33 m/s^2

F = ma = 1500 x (-3.33) = -5000 N

Answer: Braking force = 5000 N opposing the direction of motion.

NCERT Example — Impulse to bring object to rest

Question: A ball of mass 0.5 kg moving at 10 m/s is brought to rest by a player in 0.1 s. Find (a) the change in momentum and (b) the average force applied by the player.

Solution:

m = 0.5 kg, u = 10 m/s, v = 0, t = 0.1 s

(a) Change in momentum = mv - mu = (0.5)(0) - (0.5)(10) = -5 kg m/s

Magnitude of change in momentum = 5 kg m/s

(b) Force = change in momentum / time = 5 / 0.1 = 50 N

Answer: Change in momentum = 5 kg m/s; Force applied = 50 N (opposing motion).

NCERT Example — Two-object collision, finding final velocity of one

Question: Two objects of mass 100 g and 200 g move along the same line in the same direction with velocities 2 m/s and 1 m/s respectively. They collide, and after collision the 100 g object moves at 1.67 m/s. Find the velocity of the 200 g object after collision.

Solution:

m_1 = 0.1 kg, u_1 = 2 m/s; m_2 = 0.2 kg, u_2 = 1 m/s; v_1 = 1.67 m/s; v_2 = ?

By conservation of momentum:

m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

(0.1)(2) + (0.2)(1) = (0.1)(1.67) + (0.2)(v_2)

0.2 + 0.2 = 0.167 + 0.2 v_2

0.4 - 0.167 = 0.2 v_2

0.233 = 0.2 v_2

v_2 = 1.165 m/s

Answer: The 200 g object moves at approximately 1.17 m/s in the same direction after the collision.

NCERT Example — Time needed for force to produce given velocity

Question: How long should a force of 100 N act on a body of mass 10 kg, initially at rest, to give it a velocity of 20 m/s?

Solution:

F = 100 N, m = 10 kg, u = 0, v = 20 m/s

Using impulse: F x t = m(v - u)

100 x t = 10 x (20 - 0) = 200

t = 200/100 = 2 s

Answer: The force must act for 2 seconds.

Practice MCQs
1. An object of mass 2 kg moves with velocity 3 m/s. What is its momentum?
  1. 1.5 kg m/s
  2. 5 kg m/s
  3. 6 kg m/s
  4. 9 kg m/s
Answer: (C) p = mv = 2 x 3 = 6 kg m/s.
2. A net force of 50 N acts on an object of mass 10 kg. The acceleration produced is:
  1. 500 m/s^2
  2. 5 m/s^2
  3. 0.2 m/s^2
  4. 50 m/s^2
Answer: (B) a = F/m = 50/10 = 5 m/s^2.
3. Newton's First Law is also known as the:
  1. Law of Acceleration
  2. Law of Inertia
  3. Law of Reaction
  4. Law of Momentum
Answer: (B) The First Law defines inertia and is therefore called the Law of Inertia.
4. Action and reaction forces in Newton's Third Law:
  1. Act on the same body in the same direction
  2. Act on the same body in opposite directions and cancel
  3. Act on two different bodies
  4. Act only during collisions
Answer: (C) Action and reaction always act on two different bodies and therefore cannot cancel each other.
5. A bullet of mass 10 g is fired at 400 m/s. Its momentum is:
  1. 4 kg m/s
  2. 40 kg m/s
  3. 0.04 kg m/s
  4. 400 kg m/s
Answer: (A) p = mv = 0.010 x 400 = 4 kg m/s.
6. The SI unit of impulse is:
  1. kg m/s^2
  2. N/s
  3. N s
  4. kg/s
Answer: (C) Impulse = F x t, unit = N x s = N s. This is also equal to kg m/s.
7. A bus brakes suddenly and passengers jerk forward. This is an example of:
  1. Inertia of rest
  2. Inertia of direction
  3. Inertia of motion
  4. Newton's Third Law
Answer: (C) Passengers' bodies tend to continue moving forward when the bus stops — inertia of motion.
8. The total momentum of an isolated system after a collision compared to before is:
  1. Greater
  2. Smaller
  3. Equal (unchanged)
  4. Zero always
Answer: (C) Law of Conservation of Momentum: total momentum is constant in the absence of external unbalanced force.
9. A force of 20 N acts on a body for 4 s. The impulse delivered is:
  1. 5 N s
  2. 80 N s
  3. 24 N s
  4. 16 N s
Answer: (B) Impulse = F x t = 20 x 4 = 80 N s.
10. A gun of mass 3 kg fires a bullet of mass 30 g at 500 m/s. The recoil speed of the gun is:
  1. 15 m/s
  2. 5 m/s
  3. 50 m/s
  4. 150 m/s
Answer: (B) By conservation: 0 = (0.030)(500) + (3)(V). 15 + 3V = 0. V = -5 m/s. Recoil speed = 5 m/s.
11. The physical quantity that measures inertia of an object is its:
  1. Velocity
  2. Weight
  3. Mass
  4. Momentum
Answer: (C) NCERT explicitly states: "The mass of an object is a measure of its inertia."
12. A force F acts on mass m for time t from rest. The final velocity acquired is:
  1. Ft/m
  2. Fm/t
  3. mt/F
  4. F/(mt)
Answer: (A) From impulse-momentum theorem: Ft = mv - 0 = mv, so v = Ft/m.
Assertion-Reason Questions
A: A heavy truck is more difficult to stop than a light car moving at the same speed. R: The truck has greater inertia because of its larger mass.
Answer: Both A and R are true, and R is the correct explanation of A. Greater mass means greater momentum at the same speed. A larger impulse (force x time) is needed to bring the truck to rest, so it is harder to stop. Mass is the measure of inertia — this directly explains the observation.
A: A rocket moves forward when gases are expelled backward. R: This is an application of Newton's Third Law of Motion.
Answer: Both A and R are true, and R is the correct explanation of A. The expelled gases (action, backward) exert an equal and opposite force on the rocket (reaction, forward), propelling it. No air is needed, so rockets work in space.
Previous-Year Questions (CBSE)
PYQ 1. State Newton's Second Law of Motion. Derive the equation F = ma from the definition of momentum. (CBSE 2019, 3 marks)
Answer: Statement: The rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of force. Derivation: Let initial velocity = u, final velocity = v, time = t, mass = m. Rate of change of momentum = m(v - u)/t = ma (since a = (v-u)/t). Therefore F = ma. The SI unit is newton (N), where 1 N = 1 kg m/s^2.
PYQ 2. A bullet of mass 20 g is fired from a gun of mass 5 kg with velocity 400 m/s. Calculate the recoil velocity of the gun. (CBSE 2020, 3 marks)
Answer: m_bullet = 0.020 kg, v = 400 m/s, M_gun = 5 kg, V = ? Before firing, total momentum = 0. Conservation of momentum: m_bullet x v + M_gun x V = 0. (0.020)(400) + 5V = 0. 8 + 5V = 0. V = -1.6 m/s. The gun recoils at 1.6 m/s in the direction opposite to the bullet.
PYQ 3. Explain with the help of Newton's Second Law why a cricketer pulls his hands back while catching a fast-moving ball. (CBSE 2018, 2 marks)
Answer: The ball has momentum mv. To stop it, the change in momentum (impulse) = mv (fixed). Impulse = Force x time. By pulling hands backward, the time of contact t increases. Therefore Force = impulse/t decreases. The reduced force on the fielder's hands prevents injury. This is a direct application of Newton's Second Law (F = rate of change of momentum).
PYQ 4. State and derive the Law of Conservation of Momentum using Newton's Third Law. (CBSE 2022, 5 marks)
Statement: Total momentum of an isolated system remains constant provided no external unbalanced force acts on it. Derivation: Consider objects A (mass m_A) and B (mass m_B) with initial velocities u_A and u_B, interacting for time t. By Newton's 3rd Law: F_AB = -F_BA. By Newton's 2nd Law: m_A(v_A - u_A)/t = -m_B(v_B - u_B)/t. Rearranging: m_A u_A + m_B u_B = m_A v_A + m_B v_B. Hence total initial momentum = total final momentum.
PYQ 5. Define inertia. Give one example each of inertia of rest, inertia of motion, and inertia of direction. (CBSE 2021, 3 marks)
Inertia: The tendency of an object to resist change in its state of rest or uniform motion. (1) Inertia of rest: When a bus starts suddenly, passengers fall backward — their bodies tend to remain at rest. (2) Inertia of motion: A passenger jerks forward when a bus brakes suddenly — their body tends to continue moving. (3) Inertia of direction: A stone tied to a string and whirled in a circle flies off tangentially when the string breaks — it tends to continue in the direction it was moving at that instant.
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